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X^2-15X-240=0
a = 1; b = -15; c = -240;
Δ = b2-4ac
Δ = -152-4·1·(-240)
Δ = 1185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{1185}}{2*1}=\frac{15-\sqrt{1185}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{1185}}{2*1}=\frac{15+\sqrt{1185}}{2} $
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